PCAP

initially i value is 0, while condition fails as not equal to 0 So, it enters into else block and execute the increment statement. Now i become 1

Selected Answer: A
i = 0
while i !=0:
 i = i -1
else:
 i= i+1
print(i)
#output: 1

I just pass the e xam, be aware, 50% of same questions on exam, 25 are derivatives of existing ones, 25% new question

indeed, with the space, we have a SyntaxError.

if there is an space between ! = it will fail

Selected Answer: A
i = 0
print(f"initial-value: {i}")
while i != 0:
 i = i - 1
 print(f"while-value: {i}")
else:
 i = i + 1
 print(f"else-value: {i}")

print(f"final-value: {i}")

initial-value: 0
else-value: 1
final-value: 1

Selected Answer: A
A is correct, condition for the WHILE loop is never satisfied hence the ELSE part is executed.

i=1
i=1
i=1
i=1
i=1
i=1
i=1
i=1
i=1
i=1
i=1
i=1
i=1
i=1
i=1
i=1
i=1

The answer should be A because i is 0 in the first line, which means While won't be execute, then direct goes in to else section. i = i +1 which means i = 0+1, the result is 1.

The value of the i variable when the while loop finishes its execution will be 1. This is because the else clause of the while loop will be executed only if the condition of the loop (i != 0) is not met, which means that the loop will not be executed at all. Since the loop is not executed, the value of i will not be changed, and it will remain 0. However, the else clause will be executed, which contains the statement i = i + 1. This will set the value of i to 1, which is the final value of i when the loop finishes its execution.

To add to my previous comment the question is what is the variable after the while loop is run, it does not ask after the else?

is it possible that the answer is D, the variable becomes unavailable? Technically the else statement
 is: 0 = 0 + 1, we are saying nothing is equals to something? I know when we run the code and add a print statement the returned value is 1, but the code snipped does not include a print statement, so when the code is run without a print statement, we have to assume the answer is D noting is returned?

Selected Answer: A
In [4]: i=0
In [5]: while i != 0:
 ...: i=i-1
 ...: else:
 ...: i=i+1
 ...:
In [6]: i
Out[6]: 1

A is correct.
First i is given the value of 0.
The next line says "if i is not equal to 0, then decrease i's value by 1". The value of i is currently 0, so this condition does not apply and the programme proceeds to the "else" part, which is "add 1 to i". The value of i is 0, so adding 1 gets you 1.

Selected Answer: D
the answer should be D you can try it for your self as well if u want:
i = 0
while i ! = 0 :
 i=i-1
else:
 i=i+1
 print(i)

Not sure but the question is not: What is the expected output of the following code? but it is: What will be the value of the i variable when the while loop finishes its execution? If we print i before increment in the else block it will give us 0: as example below:
i=0
while i != 0:
 i = i-1
else:
 print(i)
 i=i+1
 print(i)
#output: 
"""
0
1
"""

i = 0
check while loop condition, fail
go to else block, add 1 to i
i = 1
end

What will be the value of the i variable when the while e loop finishes its execution?
//IMG//

Since the else is indented incorrectly, the code will be erroneous!

Selected Answer: D
Selected Answer: D. The code is erroneous

Selected Answer: D
else in indented wrongly

Selected Answer: A
There are many screens with indented issue - I ignore them. 
I would go for : Correct A

Selected Answer: D
The "else" part is not correctly indented

Selected Answer: D
There are 2 mistakes 
Firstly, there is missed quotes 
Secondly, the else is not indented correctly

Selected Answer: D
Just tested this code and the "else:" has the wrong indentation and therefore, it never worked.

Selected Answer: D
"else" indentation is not correct. so the answer is D. if the indentation is correct, the ans will be 3

Selected Answer: D
The indentation is not correct

If the indentation is correct then answer is 3
a=2
if a>0:
 a+=1
else:
 a-=1
print(a)

If the indentation is not correct, the answer is "the code will be erroneous"
a=2
if a>0:
 a+=1
 else:
 a-=1
print(a)

Selected Answer: D
code is not indented properly. 
Output : line number <number> invalid syntax
else:
^^^^

Answer is D, There is indentation mistake.

Selected Answer: D
The code is erroneous.

follow the indentation of the question, the answer is D

indentation is incorrect:
D. the code is erroneous

Selected Answer: D
Option D: if ran as in the question, it throws "invalid syntax" error

In the answer given, the indentation error is fixed, therefore the answer would be 3.
But because the else is not indented properly in the question, when you run the code it will give an error. Tried this in python itself and a compiler.

What is the expected output of the following snippet?
//IMG//

Selected Answer: CD
C. the constructor is a method named __init__
D. the constructor must have at least one parameter <<<< at least it should have "self" parameter

What is true about Python class constructors? (Choose two.)

Selected Answer: AB
A and B are correct ones

Selected Answer: AB
A. isinstance (obj_b,A)
B. A.VarA == 1

>>> isinstance(obj_b, A)
True
>>> A.VarA == 1
True
>>> obj_a is obj_aa
False
>>> B.VarA == 1
False

That's correct, try this code:

class A:
 VarA = 1
 def __init__(self) -> None:
 self.prop_a=1

class B(A):
 VarA = 2
 def __init__(self) -> None:
 self.prop_b=2

obj_a = A()
obj_aa = A()

obj_b=B()
obj_bb=B()

print(isinstance(obj_b,A))

print(A.VarA==1)

print(obj_a is obj_aa)

print(B.VarA == 1)

Assuming that the following piece of code has been executed successfully, which of the expressions evaluate to True? (Choose two.)
//IMG//

There is a typo in answer C. "var" should be capitalized "Var":

class Class:
 Var = data = 1
 def __init__(self,value):
 self.prop = value

Object = Class(2)

print(len(Class.__dict__) == 1) # False
print("data" in Class.__dict__) # True
print("Var" in Class.__dict__) # True
print("data" in Object.__dict__) # False

print(Class.__dict__)
print("*************")
print(Object.__dict__)

print(isinstance(obj_b,A)) # ans A, The isinstance() function returns True 
 # if the specified object is of the specified type
 # return false

print(A.VarA ==1) # ans B, A.VarA = 1, so A.VarA ==1. Then,it return true

print(obj_a is obj_aa) # ans C, return false

print(B.VarA == 1) # ans D, B.VarA = 2, so B.VarA not == 1. Then, it return false

The correct answer should be B,C

Selected Answer: BC
Correct Answer should be BC

Selected Answer: B
only correct answer is:
B. 'data' in Class.__dict__

If it was 'Var' instead, also:
C. 'var' in Class.__dict__

Selected Answer: BC
>>> Object.__dict__
{'prop': 2}
>>> Class.__dict__
mappingproxy({'__module__': '__main__', 'Var': 1, 'data': 1, '__init__': <function Class.__init__ at 0x100efd040>, '__dict__': <attribute '__dict__' of 'Class' objects>, '__weakref__': <attribute '__weakref__' of 'Class' objects>, '__doc__': None})
>>>

Assuming that the code below has been executed successfully, which of the expressions evaluate to True? (Choose two.)
//IMG//

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